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Commit 5ab62425 authored by M.D. Driver's avatar M.D. Driver
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update comment.

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......@@ -11,8 +11,21 @@ where R is gas constant,
T is temperature,
K is association constant,
theta is fractional occupancy of the phase,
S1, S2 are the solvation energy of SSIP 1 and 2 respectively.
S1, S2 are the solvation energy of SSIP 1 and 2 respectively. This is just
the binding energy contribution, \delta G_{b}.
First term in expression. Derivation:
Consider SSIPs i and j that interact, K_{ij}!=1, and assume self interaction is zero.
[i] = [i_{free}] + K[i_{free}][j_{free}]
and noting that [i_{free}] = [j_{free}]
probability that SSIP is unbound is:
P_{f} = [i_{free}]/[i] = -1 + sqrt(1 + 4K*theta)]/[2K*theta]
so the correction per SSIP is
R* T * ln( [-1 + sqrt(1 + 4K*theta)]/[2K*theta])
Since both SSIPs have a probility of being free then this becomes
2*R * T * ln( [-1 + sqrt(1 + 4K*theta)]/[2K*theta])
@author: mark
"""
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